divide by 2 on both sides => | x-10|< 3/2
now either x -10 < 3/2 or -(x-10) < 3/2
if x-10 < 3/2 then x< 3/2 +10
in this case x <11.5
if -x+10 <3/2 then x > 10 - 3/2
in this case x > 8.5
so we see that 8.5 < x <11.5
what is this in interval notation (8.5,11.5)
The last thing we should do is check our answer so lets pick a couple numbers to see if everything worked, (you don't need to do this but it always helps if you check your work)
here are two that should work:
9 for instance 2|9-10| = 2|-1| = 2 < 3 so 9 checks out
11 : 2|11-10| = 2|1| =2 < 3 so 11 checks out
2007-04-12 12:36:16
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answer #1
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answered by marvin0258 3
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6-10
2007-04-12 19:26:04
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answer #2
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answered by hi_everyone 3
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2|x - 10| < 3
|x - 10| < 3/2
-3/2 < x < 3/2
17/2 < x < 23/2
x is an element of [17/2, 23/2]
2007-04-12 20:02:33
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answer #3
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answered by Northstar 7
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|x-10| < 3/2
x - 10 < 3/2 and x - 10> -3/2
x < 11 1/2 and x > 8 1/2
8 1/2 < x < 11 1/2
2007-04-12 19:25:49
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answer #4
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answered by richardwptljc 6
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divide both sides by two, giving you
|x-10| < 1.5
because it is an absolute value we have to set up an two inequalities.
so x-10 < 1.5
and -x +10 < 1.5
soliving gives us x > 8.5 and x < 11.5, which in interval notation, looks like: (8.5, 11.5)
2007-04-12 19:27:36
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answer #5
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answered by ǝɔnɐs ǝɯosǝʍɐ Lazarus'd- DEI 6
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