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how do you find the slope, y intercept and x intercept in this problem: 2x-9y-45=0.
please explain how.

2007-04-12 11:16:51 · 4 answers · asked by Justin K 2 in Science & Mathematics Mathematics

4 answers

To find the y-intercept, you let x=0 and then solve for y; to find the x-intercept you let y=0 and solve for x. For example, by letting x=0 you get -9y-45=0 which is the same as -9y=45--or y=-5 is your y intercept. Let y=0 and solve to get your x-intercept.

2007-04-12 11:22:41 · answer #1 · answered by bruinfan 7 · 1 0

2x-9y-45=0
First if we put this into y=mx+b form we will answer 2 of the 3 questions.

2x-9y-45=0
Add 9y to both sides
2x-45=9y
Flip it around
9y=2x-45
divide by 9
y=2/9 x - 5
The y intercept is -5, the slope is 2/9
To find the x intercept, solve for x
2x-9y-45=0
Add 9y and 45 to both sides
2x=9y+45
Divide by 2
x=9/2 y + 45/2, the x intercept is 45/2 = 22 1/2

2007-04-12 18:24:33 · answer #2 · answered by danjlil_43515 4 · 0 0

put the slope into slope intercept form y = mx + b ( or basically means isolate y)

2x - 9y - 45 = 0

add 45 for both sides
2x - 9y = 45

subtract 2x for both sides
-9y = -2x + 45

divide -9 for both sides
y = 2/9x - 5

slope is 2/9

plug 0 for y to get x-intercept
plug 0 for x to get y-inercept

2007-04-12 18:25:56 · answer #3 · answered by      7 · 0 0

2x-9y-45=0
2x-9y=-45.
I'm stuck.

2007-04-12 18:26:44 · answer #4 · answered by zxcvbnm6 3 · 0 0

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