In a field the # of pigs & geese is 20.The total # of legs is 70,How many pigs & how many geese r in the field

Question

please show how u got it

Answer 1

15 pigs and 5 geese

15*4 pig legs = 60

5 * 2 geese legs = 10

Answer 2

let's set up 2 equations and figure it out that way.

pigs have 4 legs, geese have 2. Use p for pig, and g or geese legs.

4p + 2g = 70
p + g = 20

Take second equation:
p+g = 20
p = 20-g

Plug this into first equation.
4(20-g) + 2g = 70
80-4g+2g = 70
80 - 2g = 70
80 = 70 + 2g
2g = 10
g = 5

Well, if there are 5 geese, then that means 10 legs. Subtract that from 70, is 60. That means that there must be 60/4 pigs in the field.

Therefore, there are 5 geese and 15 pigs in this field. =)
HOpe this helped!

Answer 3

Just hope you don't have weird mutant pigs and geese.
Let p be the number of pigs
Let 20-p be the number of geese.
For any of these problems, you should state the relationship you use to set-up the solution.
Legs = # of animalsx legs/animal.
For pigs, legs = 4p
For geese, legs =2 (20-p)
For both 70 = 4p+ 2(20-p), from which p=15,
20-p= 5.

Answer 4

it's best to do a system of equations for this... we'll call p our # of pigs and g our # of geese.

First equation... problem says "# of pigs & geese is 20" , so that means that: p + g = 20

Second Equation... problem says "# of legs is 70", so assuming that every pig has 4 legs and every goose has 2 legs, we'd do this: 4p + 2g = 70

So we have:
p + g = 20
4p + 2g = 70

I'll solve by substitution.
p + g = 20 means that p = 20 - g <-- subtracting g from both sides
so let's substitute that in the second equation
4(20 - g) + 2g = 70
80 - 4g + 2g = 70
80 - 2g = 70
-2g = -10
g = 5

now to get how many pigs are in the field, we can pop 5 into the first equation for g and solve for p...
we'd get p = 15

15 pigs and 5 geese

Answer 5

let x stand for pigs and y stand for geese

x + y = 20

pigs have 4 legs and geese have 2, so 4x + 2y = 70

4x + 2(20-x) = 70
2x +40=70
2x=30
x=15
y=5
15 pigs and 5 geese

Answer 6

15 pigs and 5 geese.
(60 legs) (10 legs)

Answer 7

p + g = 20 ====> P +g = 20
4p + 2g =70 ===>2p+g = 35
Subtract, we get p =15
so p=15 and g = 5

5 geese and 15 pigs

:)

Answer 8

Make 20 circles - attach 2 legs to each circle - then go back and attach 2 more legs to each circle until you are out of legs - there's the answer! We were given this problem in a math class and we, being math students, went about setting up the equations and solving them. Then the teacher showed us the above solution. It is easier and faster. We were blinded by our assumptions as math students.
Marilyn vos Savant had this problem in the Parade magazine. Is that where you saw it?

Answer 9

2x+2y = 40
2x +4y=70

2y=30
y=15

15 pigs and 5 geese