What is the probability of getting exactly four heads when a fair coin is flipped eight times?

Answer 1

Each coin has two possibilities and there are eight coins. 2 to the power of eight is 256.

So now you only need to know how many ways you can make only four heads which probably is 8!/4!*(8-4)! = 70

Probability is 27.34% or exactly twice that of scythian who got his powers of two wrong..

Now the next question is, which one, if any of us has the right answer?

Answer 2

There are 2^8 = 512 possible outcomes from flipping a coin 8 times, but there's only 8!/4!(8-4)! = 70 ways for exactly 4 heads to show up, so that comes to 70/512, or about 13.67% probability.

Addendum: A pox on Peter K for having pointed out my trivial arithmetic mistake, it was the thought that counted. Okay, it's 70/256, or 27.34%

Answer 3

Ok, if you flip a coin once it has 50 percent chance either way
to land on same side once more however changes to favor of the other side will be landed on. Thou its 50 percent chance. either way no matter how many times you toss it. but landing on heads 4 our of 8 straing in a row
1/2 = 50%
4/8 = 50% as well