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first to ethanal and then to ethanoic acid. Using the data calculate the change in H for the second oxidation. We were given the heat of combustion for ethanol, ethanal and ethanoic acid as -1371 kJ/mo, -1168 kJ/mol, and -876 kJ/mol respectively. Please help and I would appreciate if you outline the steps as I am extremely lost...!

2007-04-12 08:18:18 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

A Hess Cycle approach would show you that the enthalpy change for the second oxidation is -1168 -(-876).

CH3CHO + [O] ----> CH3COOH

2007-04-12 08:49:55 · answer #1 · answered by Gervald F 7 · 0 0

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