(x + 18)(x + 2) = 0
x = -18 or x = -2.
2007-04-12 08:15:06
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answer #1
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answered by Anonymous
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Easiest way to do this one is by factoring...
we need 2 numbers that multiply to get 36 and add to get 20, our numbers are 18 and 2, so we do this
x^2 + 20x + 36 = 0
(x + 18)(x + 2) = 0
By the zero product rule, x + 18 = 0 or x + 2 = 0, so we solve our 2 equations....
x + 18 = 0 x + 2 = 0
x = - 18 x = -2
so, our 2 solutions are x = -2 or x = -18
2007-04-12 15:14:05
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answer #2
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answered by Anthony T 3
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x^2 + 20x + 36 = 0
x^2 + 2x*10 + 100 - 100 + 36 = 0
(x + 10)^2 - 64 = 0
(x + 10 - 8)(x + 10 + 8) = 0
(x + 2)(x + 18) = 0
x1 = -2
x2 = -18
2007-04-12 15:16:13
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answer #3
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answered by Amit Y 5
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x^2+20x+36=0
First factor it
(x+2)(x+18) set each equal to 0
x+2 = 0 subtract 2 from both sides
x = -2
x+18 = 0 subtract 18 from both sides
x = -18
Then check your answer by putting -2 and - 18 back into
x^2+20x+36=0 for x to see if its true.
(-2)^2+20(-2)+36=0 True
(-18)^2+20(-18)+36=0 True
2007-04-12 15:18:12
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answer #4
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answered by Pam 5
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First, try to factor, then use the zero property rule.
(x+18)(x+2) = 0
so either x+18 = 0 or x+2 = 0
answers are x= -18 or x = -2
If you did not figure out the factors, you can always resort to the quadratic formula, which recall is
x = (-b+/-sqrt(b^2-4ac) ) / (2a)
For your problem a=1 b=20 and c=36
x = (-20 +/- sqrt(400-4(1)(36)) / (2)
simplify:
= (-20 +/- rt (256) ) /(2)
=(-20 +/- 16 ) / 2
= -36/2 OR -4/2
= -18 OR -2
either method, you will get the same result.
2007-04-12 15:19:23
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answer #5
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answered by MathMark 3
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x^2 + 20x + 36 = 0
(x + 2)(x + 18) = 0
x + 2 = 0 or x + 18 = 0
x = -2 or -18
2007-04-12 15:14:40
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answer #6
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answered by chichow.duckie 2
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factor: what multiplied together gives you 36,
1 , 36
2, 18
3, 12
4, 9
6, 6
but added together gives you 20? 2 and 18
(future note: if you can not factor, use quadratic formula)
so (x + 2)(x + 18) = 0
set each parenthesis equal to zero and solve for x: x = -18, x = -2
2007-04-12 15:17:53
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answer #7
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answered by Ana 4
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(x + 18)(x + 2) = 0
x = -18, x = -2
2007-04-12 15:13:26
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answer #8
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answered by fcas80 7
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There are many websites online which solve quadratic equations for you :D!!! (Okay, If you are learning this for school, I suggest you actually learn and try it on your own).
http://www.1728.com/quadratc.htm
The answers by the way are
x1= -2 and
X2= -18
2007-04-12 15:18:46
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answer #9
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answered by Sithara B 2
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Quadratic formula or Ti-graphing calculator.
2007-04-12 15:13:52
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answer #10
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answered by dwinbaycity 5
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