A temperature of 10 Celcius degrees corresponds to a temperature of 50 degrees Ferenheit.?

Question

Also 40 degrees celcius corresponds to 104 degrees Farenheit. Find the linear equation relating F and C.

Answer 1

Fahrenheit Formula

F = 9/5C + 32

F = 9/5(10) + 32

F = 90/5 + 32

F = 18 + 32

F = 50°

- - - - - - -

F + 9/5C + 32

F = 9/5(40) + 32

F = 360/ 5 + 32

F = 72 + 32

F = 104°

- - - - - - - -s-

Answer 2

I got two temperature formulas here. One for converting from Celcius to Farenheit and one for comverting from Farenheit to Celcius.

First: A temperature of 10 Celcius degrees corresponds to a temperature of 50 degrees Farenheit?

Well, lets check and see.

degrees (F) = degrees (C) x 1.8 + 32
degrees (F) = 10 x 1.8 + 32
degrees (F) = 18 + 32
degrees (F) = 50 .... I believe it works.

Go the other way:

degrees (C) = [ degrees (F) - 32] / 1.8
degrees (C) = ( 50 - 32 ) / 1.8
degrees (C) = ( 18 ) / 1.8
degrees (C) = 10 ... Looks good to me.

* * * * * * * * * * * * * * * * * *

For every 1 degree (C) rise, (F) rises by how much?

Let C=1, 2, 3, 4, 5

F = C x 1.8 + 32

....= 1 x 1.8 + 32 = 33.8 (F)
....= 2 x 1.8 + 32 = 35.6 (F)
....= 3 x 1.8 + 32 = 37.4 (F)
....= 4 x 1.8 + 32 = 39.2 (F)
....= 5 x 1.8 + 32 = 41.0 (F)

Looks to me like that for every 1 degree rise in Celcius there is a 1.8 degree rise in Farenheit.

Hmmmm. Let's go the other way just for fun.

For every degree (F) rise, how much does (C) rise?

Let F=32, 33, 34, 35

C = ( F - 32 ) / 1.8

....= ( 32 - 32 ) / 1.8 = 0 (C)
....= ( 33 - 32 ) / 1.8 = 0.556 (C)
....= ( 34 - 32 ) / 1.8 = 1.111 (C)
....= ( 35 - 32 ) / 1.8 = 1.666 (C)

Looks to me like for every 1 degree rise in Farenheit there
is a 0.555...degree rise in Celcius.

Now, what was the question?
Find the linear equation relating F and C.

Well, let's see. Hmmm.

1 / 0.555 = 1.8 -- and -- 1 / 1.8 = 0.555

therefore: From here I don't have a clue. This is where I get off the bus. It's been too many years since I've done this. One of you take it from here if you can use any of this. If you can't then just use it for a good laugh.

Answer 3

Just use the formula
9X/5 + 32

X=Degrees C

Thus 9*10 / 5 +32 = Degrees F

Answer 4

You have two points on a graph - (10, 50) and (40, 104)

You can calculate slope m by using this equation:
m = (y2-y1)/(x2-x1)

Then plug one of those points, and m, into this equation:

y=mx + b

To find b, the y-intercept.

y is fahrenheit, x is celcius.

Answer 5

Years ago, I always kept a wet bandana around my neck.... sometimes I'd keep one in the fridge (which wouldn't help you without power), and one around my neck and just kept changing them as needed. However, last summer while on a camping trip during a miserable heatwave, I discovered this product that is great! It's the same idea as the bandana, but it's filled with something (mystery to me) that stays wet and cool for a long time - they can be found at places like CVS, Rite-Aid, Walgreens - maybe Target too. You simply soak this thing in water until it's completely absorbed and then you fasten it around your neck. The theory is that the blood supply in your neck will be cooled as it travels up and down. For me, if my head is cool, I'm fine. Another trick is to have a tub with enough water to come up to your ankle - simply keep your bare feet in it. This can only be used when you're sitting - as opposed to the bandana around the neck, which can be used while working. Hope this helps! BTW, where are you? Iraq? ~ Connie in California

Answer 6

just plot both pairs of points on a graph and calculate the slope