Math help!?

Question

i was sick the week this was taught, please help me understand
determine the x intercept and the y intercept of 4x-2y=10.

Answer 1

To find x intercept, set y as zero then solve, and vice versa for y intercept.

x intercept = 2.5
y intercept= -5

Answer 2

The x intercept occurs when y = 0, right?
And the y intercept occurs when x = 0.

So do that. For the x intercept, set y to zero and solve the equation

4x -2(0) = 10
4x = 10
x = 2.5

For the y intercept, set x to zero and solve
4(0) -2y = 10
-2y = 10
y = -5

Answer 3

Just set value of one variable to zero and solve for other.
4(0) - 2y=10 y= -5 Y-intercept (0,-5)
4x-2(0)=10 4x=10 x=10/4 x=2.5 X-intercept (2.5,0)

Answer 4

The x-intercept is when y = 0. Plug in 0 for y and solve for x.
The y-intercept is when x = 0. Plgu in 0 for x and solve for y.

x-int:
4x - 2y = 10
4x - 2(0) = 10
4x = 10
x = 5/2 = 2.5

y-int:
4x - 2y = 10
4(0) - 2y = 10
-2y = 10
y = -5

Answer 5

to find x-intercept, set y=0, and solve for x:
4x=10
x=2.5

to find y-intercept, set x=0 and solve for y:
-2y=10
y=-5

Answer 6

for the y-intercept, x=0.
Then the equation is -2y=10
then y=-5
the y-intercept is (0,-5)
for the x-intercept, y=0
then the equation is 4x=10
then x=2.5
the x-intercept is (2.5,0)