Bond enthalpy of a C-F bond is +467kJ-1, how to calculate minimum energy needed to break single a C-F bond.?

Question

needs to be done in joules, any help is much appreciated!

Avagadro Constant, L=6.02x10^23mol^-1

Answer 1

1. multiply 467 by 1,000 to get Joules
2. divide by Avogadro's number.

Answer 2

bond enthalpy of reactants (R) is C=C + 4 C-H +H-H= 612+4C-H+436=1048+4C-H bond enthalpy of prodcuts (P) = C-C+ 6 C-H= 348+6C-H DELTA H= R-P or, -136=1048+4C-H-348-6C-H or. C-H= 418