x^2-x-6=0 (that is xsquared)!?

Question

What is X? And how do you figure it out?

Answer 1

x²-x-6=0

This is a quadratic equation.

You can solve it by factorizing or with the quadratic formula.

1) FACTORIZING

x²-1x-6=0

-6 = -3 · 2
-1 = -3 + 2

(x-3)(x+2) = 0
x=3, x=-2

2) QUADRATIC FORMULA

In general, the solutions of a quadratic equation
Ax² + Bx + C = 0
can be found with the quadratic formula:
x = [ -B ± √(B² - 4AC) ] / [2A] .

In your case the coefficients are:
A = 1
B = -1
C = -6

Plug them in the quadratic formula:
x = [ 1 ± √((-1)² - 4·1·(-6)) ] / [2·1]
x = [ 1 ± √(1 + 24) ] / 2
x = [ 1 ± √25 ] / 2
x = [ 1 ± 5 ] / 2

x = [ 1 + 5 ] / 2 = 6/2 = 3
x = [ 1 - 5 ] / 2 = -4/2 = -2

Hope this helps!

Answer 2

x^2 - x - 6 = 0 can be expressed as x + 2 multiplied by x - 3 and so can be written as (x + 2) (x - 3) = 0

So, x + 2 = 0 is one solution and so x = -2

x - 3 = 0 is the second solution and so x = 3

So, x = 3 and -2

Answer 3

y=5x-6 and y=x^2 we equate them i.e. x^2=5x-6 as both are equivalent to y so that they are equivalent then x^2-5x+6=0 x^2-3x-2x+6=0 x(x-3)-2(x-3)=0 (x-2)(x-3)=0 so x=2,3 for x=2, y=(2)^2=4 and for x=3, y=9 (2,4) and (3,9) are the factors of the intersection.

Answer 4

(x-3)(x+2) x=3 or -2

Answer 5

x^2-3x+2x-6
(x+2)(x-3)
x=-2 or x=3

Answer 6

use the formula

[-b +/- the square root of (b^2 -4ac)]
divided by 2a