Do you mean (-7/-6) · 5 · (4/-7) ?
(-7/-6) · 5 · (4/-7) =
7/6 · 5/1 · (-4/7) =
- (7·5·4)/(6·1·7)
Now 7 on the top cancels out with the 7 on the bottom and
the 4 on the top and the 6 on the bottom have 2 as a common factor so that 2 cancels out, too and you get
- (5·2)/(3) = -10/3
Hope this helps.
2007-04-12 06:49:41
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answer #1
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answered by M 6
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here that's: -7/3= -2 a million/3 and 9/-4= -2 a million/4 Inorder to function those 2 mixed numbers you could ought to locate the backside hassle-unfastened denominator (lcd). For this problem the the lcd = 12. -2 a million/3 = -2 4/12 and -2 a million/4 = -2 3/12 subsequently, -2 4/12 + -2 3/12 = -4 5/12 ( you could upload the two mixed numbers sinse the lcd are in hassle-unfastened) #2 Any selection which would be expressed as an entire selection is assessed as an integer. Definition: The set of integers consists of the helpful integers, destructive integers, and nil. {...-3,-2,-a million,0, a million, 2, 3,.....} subsequently, -80 one, 12/3=4, and 18/9 are the only numbers that qualify as an integer.
2016-12-09 01:13:44
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answer #2
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answered by Anonymous
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You people REALLY need to use parantheses to help us out with these problems
ie:
(-7/-6) x 5 x (4/-7)
If this is the problem then here is the answer.
(7/6) x (5/1) x (-4/7) ->
(35/6) x (-4/7) = -140/42 = -10/3
2007-04-12 06:52:40
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answer #3
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answered by Anonymous
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-7/-6 = + 7/6
That multiplied by 5 is 35/6 and that multiplied by 4/-7 will give us (35 X 4) / (6 X -7) = - 5 X 2/ 3 = -10/3
2007-04-12 06:54:57
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answer #4
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answered by Swamy 7
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( -7 / -6 )5( 4 / -7 )
(35 / 6)(4 / -7)
(-10 / 3)
2007-04-12 06:53:41
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answer #5
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answered by Link 4
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answer = -10/3 = -3 and 1/3
2007-04-12 06:50:46
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answer #6
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answered by Anonymous
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