d
No one side can be greater than the sum of the other two. For the first, 20 > 8 + 10.
2007-04-12 04:14:32
·
answer #1
·
answered by gebobs 6
·
0⤊
0⤋
The answer is letter d. because of the triangle inequality theorem that states that if a, b, c are the lengths of the sides of a triangle:
a-b
having this in mind:
1. 8, 10, 20 (is not correct because 20-10=10 and it is greater than 8)
2. 16, 18, 25 (possible because 25-16=9 which is less than 18)
3. 7, 7, 7 (possible because 7-7=0 which is less than 7. it is also good to know that this is an equilateral triangle and any length of side of an equilateral triangle is possible)
2007-04-12 04:18:31
·
answer #2
·
answered by Hannah C 1
·
0⤊
0⤋
the answer is letter d. because of the triangle inequality theorem that states that if a, b, c are the lengths of the perimeters of a triangle: a-b
2016-11-23 14:37:28
·
answer #3
·
answered by ? 4
·
0⤊
0⤋
D
cos 8 + 10 is not greater than 20
2007-04-12 04:14:32
·
answer #4
·
answered by Jesk 6
·
0⤊
0⤋
the answer is d
8, 10, 20 has 1 side that is longer than the other 2 put together therefore cannot be a triangle.
2007-04-12 04:15:13
·
answer #5
·
answered by dark_massiah 3
·
0⤊
0⤋
d
When added together 8 and 10 do not make 20
2007-04-12 04:16:39
·
answer #6
·
answered by RonnyJ 3
·
0⤊
0⤋
use cosine law to find the angle.,make sure they add up to 180 The answer must include 3.
2007-04-12 04:16:25
·
answer #7
·
answered by El C 2
·
0⤊
1⤋
d
2007-04-12 04:15:02
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋