Please HELP with this acceleration question?

Question

The position in meters of a particle at time t in seconds is d(t) = 3t^3 – 17t, where t is greater-than-or-equal-to0 . Find the acceleration of the particle when t = 4

a) 124 m/s^2
b) 19 m/s^2
c) 127 m/s^2
d) 72 m/s^2

Answer 1

The second derivative of the position is the acceleration.

d' = 9t^2-17
d'' = 18t

Acceleration at t=4 is 18*4 = 72

Answer 2

there is alot better in the back of who will win .. a/c will will boost up linear.. or otherwords, a consistent fee of acceleration(with some small fluctions with the aid of pull of the wheels, flaps ) until eventually the thrust=drag. vehicles have Gears, which signifies that acceleration isn't consistent time-honored. each and each and every equipment has a multiple acceleration fee, until eventually the max skill accessible is acheived. third is skill to weight ratio- the better merchandise weighs, the better rigidity is had to boost up it. Physics one 0 one, F=MA In a short distance, a vehicle ought to win, only because of the time required for the engines to spool up, and boost up the plane, yet over a lengthy distance, the acceleration from the plane will over take the vehicle. The fastest highway legal vehicle is recorded at 253mph (Buggati Veyron) . A b747 flies at round 380kts

Answer 3

d(t) = 3t^3 – 17t
d(4) = 3(4)^3 - 17(4)
d(4) = 3(64) - 68
d(4) = 192 - 68
d(4) = 124
a) 124 m/s^2

Answer 4

How about doing your own homework?