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4 answers

OK

- 4x - 6y = 5
- 8x -12y = 10

Multiply the top equation by (-2)

8x + 12y = -10
- 8x -12y = 10

Now take the sum of the both equations

8x - 8x + 12y - 12y = -10 + 10

0 = 0

This identity is obviously valid, but doesn't give us a condition for either x or y, which means that any x and any y will solve the system.
There are infinitely many solutions.

(Graphically this means that the lines -4x-6y=5 and -8x-12y=10 coincide, i.e. they are one and the same line and as such they have infinitely many points in common )

The system is CONSISTENT (since there is a solution [ie all pairs of real numbers]. But as there are infinitely many solutions (and not only one), the system is DEPENDENT.

Hope this helps!

2007-04-12 03:13:02 · answer #1 · answered by M 6 · 4 0

-4x - 6y = 5
-8x - 12y = 10
Eliminate x:
Multiply 1st equation by 2, and subtract second:
0 = 0.
You have eliminated y as well.
The equations are therefore dependent. The second is the first multiplied by 2.

2007-04-12 10:15:22 · answer #2 · answered by Anonymous · 0 0

These equations are dependent.
If we multiply the first by 2 it becomes the second one.
Subtracting gives 0=0, i.e., the equations are
dependent(or redundant).

2007-04-12 10:26:14 · answer #3 · answered by steiner1745 7 · 0 0

Unfortunately you can't solve for x and y, since the second equation is the exact same as the first (every term is just doubled).

2007-04-12 10:14:38 · answer #4 · answered by Kyrix 6 · 0 0

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