The current in an RL circuit builds up to one third of its steady-state value in 5.00 s. Find the inductive time constant. Explain your work, and good luck! :)
2007-04-11 10:50:37 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
First you need to know the equation to use. For an inductor you have
F = 1-exp(-Lt/R)
F = Fraction of full current
L = inductance (Henries)
R = Resistance(Ohms)
t = time in seconds
So no I have explained the work and you get to plug in the numbers and solve the equation.
2007-04-11 10:56:38 · answer #1 · answered by rscanner 6 · 0⤊ 1⤋
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RE:
Inductive Time Constant...?
The current in an RL circuit builds up to one third of its steady-state value in 5.00 s. Find the inductive time constant. Explain your work, and good luck! :)
2015-08-07 02:42:32 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Lr Time Constant
2016-11-13 21:17:10 · answer #3 · answered by rhoat 4 · 0⤊ 0⤋
One time constant is e^-1, which is 0.36788
Your circuit is up to 0.333333 (in 5 seconds), which is slightly less than one time constant, so the answer will be slightly more than 5 seconds.
0.33333 = e^-x solve for x
ln(0.33333) = -x
-1.09861 = -x
1.09861 = x
Multiply 5 seconds by 1.09861 = 5.493 seconds is the time constant
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2007-04-11 11:00:06 · answer #4 · answered by tlbs101 7 · 1⤊ 0⤋