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a. 5.0g Pyrex® glass (specific heat capacity = 0.20 cal/g•K)

b. 20g platinum (specific heat capacity = 0.032 cal/g•K)

c. 1.0g water (specific heat capacity = 1.00 cal/g•K)

2007-04-09 21:03:07 · 3 answers · asked by bballchic601 1 in Science & Mathematics Chemistry

3 answers

b. 32cal/*k

2007-04-09 21:25:25 · answer #1 · answered by bige1236 4 · 0 0

Use always formula

Q= mcdT
m mass ;c specific heat capacity; dT change of temperature

So here you have for all problems dT = 65-15=50°

a) Q = 5*0.2*50 =50cal

b) Q = 20*0.032*50 =32 cal

c) = 1*1*50= 50 cal

2007-04-09 21:18:09 · answer #2 · answered by maussy 7 · 0 0

a. 50
b. 3.2
c. 50

2007-04-09 21:06:55 · answer #3 · answered by Sam 5 · 0 0

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