Solve for x and y:?

Question

2x+3y=5 and
4x+6y=8

You should find the integer values of x and y.
If you can't give me the reason.

Answer 1

2x + 3x = 5- - - - - -Equation 1
4x + 6y = 8- - - - - -Equation 2
- - - - - - - - -
Multiply equation 1 by - 2

2x + 3y = 5

-2(2x + (- 2)(3y) = - 2(5)

- 4x + (- 6y) = - 10

- 4x - 6y = - 10

- - - - - - - - - - - -
- 4x - 6y = - 10
4x + 6y = 8
- - - - - - - - -

The coefficients and variables cancell. No solution

- - - - - - - - -s-

Answer 2

No solution to answer. As 2 + 3 = 5 and 4 + 6 cannot equal to 8, if X and Y were to be 1.

Answer 3

I'm pretty sure the answer is "no solution". You would multiply the first eqation by -2. This will give you -4x-6y=-10. Now you have like terms (4x and -4x). Line them up like this:

4x+6y=8
-4x-6y=-10
__________
0=-2
The x's cancel each other out but so do the y's so you have 0.
8-10=-2. So you end up with 0=-2 which is not true. Therfore, no solution.

Answer 4

If we use linear algebra and put the equations into the form Ax=B, we find that the determinant of A is zero (see below). If you try to use Cramer's rule, you wind up dividing by zero. Therefore, no solution.

det ([2 3; 1 4])=(2*6)-(3*4)=0

BTW, linear algebra is a superior method as compared to substitution--it's capable of solving more complex problems in fewer steps.

Answer 5

This pair of equations is not solvable. If you double the 1st equation you have
4x + 6y = 10
4x + 6y cannot equal both 10 and 8.

Answer 6

x= 5/2 -3y/2
y=5/3-2x/3

x=2 - 3/2y
y=4/3 - 2x/3

i could be wrong though haha

Answer 7

NO SOLUTION BUDDY,HOW CAN U HAVE 2 EQUATIONS WITH THE SAME VALUE...........ITS LIKE UR SAYING...10=8!!!!

Answer 8

there are no real values for x and y