2007-04-09 19:35:29 · 5 answers · asked by bratt1 1 in Science & Mathematics ➔ Mathematics
= (5x^2)^3-(y^2)^3
= (5x^2-y^2)(25x^4+5x^2y^2+y^4)
2007-04-09 19:40:01 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 2⤋
Like this:
125x^6 - y^6
= (5x^2)^3 - (y^2)^3
=[(5x^2) - (y^2)] x [(5x^2)^2 + (5x^2)(y^2) + (y^2)^2]
=[(5x^2) - (y^2)] x [(25x^4) + (5x^2)(y^2) + (y^4)]
={ [(sqrt5)x - y] x [(sqrt5)x - y] } x [(25x^4) + (5x^2)(y^2) + (y^4)]
={ [(sqrt5)x - y] x [(sqrt5)x - y] } x [25x^4 + 5(xy)^2 + y^4].
2007-04-09 19:51:33 · answer #2 · answered by chancebeaube 3 · 0⤊ 0⤋
a^3-b^3=(a-b)(a^2+ab+b^2)
125x^6-y^6=(5x^2)^3-(y^2)^3
answer is
(5x^2-y^2)(25x^4+5x^2*y^2+y^4)
2007-04-09 20:38:00 · answer #3 · answered by bige1236 4 · 0⤊ 1⤋
u can't, if it was (125x-y)^6 that'd be a different story.
2007-04-09 19:40:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋
(5x^2)^3-(y^2)^3
=(5x^2-y^2)(25x^4+5x^2y^2+y^4)(ans.)
as a^3-b^3=(a-b)(a^2+ab+b^2)
2007-04-10 00:48:01 · answer #5 · answered by Anonymous · 0⤊ 1⤋