Silver has a face-centered unit cell. The diameter of a silver atom is about 2.90 angstroms. Use this measurement to calculate the density of silver (grams per centimeter cubed)
atomic weight of Silver = 107.87 g/mol
2007-04-09 19:17:39 · 2 answers · asked by evilssjtrunks65 1 in Science & Mathematics ➔ Chemistry
Convert angstroms to meters by using the conversion factor 1angstrom= 1x10^ -10 m. From meters, convert to centimeters, then cube it, which gives you the answer: 2.44x10^ 23 cm^3.
Face-centered unit cells have four atoms/cell, so use this information to get the weight of silver. The answer would be 7.17x10^ -22 g.
Density=mass/volume, plug the values onto the formula and you get the answer: 29.4g/cm3
2007-04-09 22:08:04 · answer #1 · answered by unean_amigo 3 · 0⤊ 0⤋
Each unit cell has 4 atoms
So, density is 4*107.87/(NA*(5.80/1.414)^3) = 10 380. 3514 kg/m^3
2007-04-09 22:24:41 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋