Word problem:Calculus of the trig. function?

Question

Can someone please explain how to set this word problem up. Thank you.

The foot of a 5-meter ladder leaning against a tall wall is being pulled away from the wall at the rate of 2m/s. At what rate is the ladder rotating when its foot is (a) 3 meters from the wall?

Answer 1

cosθ = x/5
-sinθdθ = dx/5
ω = dθ/dt = (1/5sinθ)dx/dt
sinθ = (1/5)√(25 - x^2)
ω = (1/√(25 - x^2))dx/dt
ω = 2/√(25 - 3^2)
ω = 2/√(25 - 9)
ω = 2/√16
ω = 2/4
ω = 1/2 rad/s

Answer 2

soory i dont know