the reaction: CO(+2charge) +6 NH3= CO(NH3)6 (+2charge)?

Question

has an equilibrium constant of .0005 M^-6. solutions were mixed sothat the initial concentration of the Cobaltous ion was 0.100M and the Ammonia was 1.00M. what are the equilibrium concentrations of all 3 species in the reaction?

Answer 1

Co(2+) + 6NH3 -> [Co(NH3)6]2+
.1 1 0

.1-x 1-6x x

So, x/[(1-6x)^6(.1-x)] = 0.0005

1-6x -> 1

So, x/.1-x = 0.0005

Solve for x

Answer 2

Co Nh3