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f(x) 1-x^(2/3) [-8,8] whats the ab max and min ?

2007-04-09 16:04:03 · 1 answers · asked by lindsay e 1 in Science & Mathematics Mathematics

1 answers

at x=0, f(x) = 1, that's your max.
as x increases or decreases away from 0, x^(2/3) increases, so f(x) decreases, and your mins are at (-8,-3) and (8,-3). The even exponent on x gives it symmetry around the y axis.

2007-04-09 16:15:29 · answer #1 · answered by Philo 7 · 0 0

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