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a solution of sodium nitrate has a concentration of 0.733 M and a density of 1.0392 g/mL

A) write the molarity as a fraction(moles/liters solution)

B) rearrange the molarity equation and solve for volume

C) find the mass of the moles of sodium nitrate







help??

thanks

<3

2007-04-09 15:40:21 · 2 answers · asked by lalagurl94 1 in Science & Mathematics Chemistry

2 answers

A) 733 moles/1000 litres

Moles of NaNO3 reqd.

2007-04-09 23:01:17 · answer #1 · answered by ag_iitkgp 7 · 0 0

I dont wanna do the calculations, you do it ( so you can actually try). I'll just say how get the number of mols of KOH... volume (in litres) x molar concentration of KOH then, check the ratio. in the equation-- 2 molecules of KOH is required to react with 1 molecule of H2SO4. so to get the number of mols of H2SO4, just dived the mols of KOH by 2 then just mols of H2SO4/volume (in litres) = molarity of H2SO4 molarity is the same as molar concentration

2016-04-01 06:21:48 · answer #2 · answered by Anonymous · 0 0

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