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What is the atomic radius, in angstroms, of nickel?

Atomic weight of Nickel = 58.71 g/mol

2007-04-09 15:38:35 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Each unit cell has 4 atoms

So, let atomic radius be a, so unit cell is of side (4a/1.414) = 2.828 a

So, density = (4*58.71)/(NA*l^3) where l is the side of the unit cell.

2007-04-09 23:01:19 · answer #1 · answered by ag_iitkgp 7 · 0 0

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