If none of the above wins...those people are out. Then we run more people until we get a winner with a majority.
2007-04-09 15:05:57 · 12 answers · asked by Laughing Man Copycat 5 in Politics & Government ➔ Elections
Absolutely
It might take five or six times around though
2007-04-09 15:10:08 · answer #1 · answered by Anonymous · 2⤊ 0⤋
Yes. The Libertarian Party primary does work this way.
Another method I heard suggested is to run the whole election like American Idol. Each week, we vote somebody out, till we're finally down to 2 or 3 choices. That's a whole lot better than letting Vermont decide what those choices will be.
2007-04-09 15:09:18 · answer #2 · answered by open4one 7 · 3⤊ 0⤋
No. You can't because it will make your ballot paper invalid and won't be counted. If none of the candidates meet the required percentage to win, the election is usually repeated.
2007-04-09 16:24:31 · answer #3 · answered by Joe Stargazer 2 · 0⤊ 1⤋
you are able to write in whomever you want. Santa Clause...your self..or not one of the ABOVE. And if maximum did that...the election might bypass to the subsequent optimum vote getter. yet that isn't in any respect ensue.
2016-10-28 07:42:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I would love to see a 'write in' place on the ballot.
2007-04-09 17:07:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
None of the above,yes then we can vote for Monica.L.
2007-04-09 15:13:44 · answer #6 · answered by Larry-Oklahoma 7 · 1⤊ 0⤋
Don't you recall how confused Democrats in Florida were in 2000 about the butterfly ballots (that they designed)? Just imagine what THIS would do!
2007-04-09 16:02:56 · answer #7 · answered by jdkilp 7 · 1⤊ 1⤋
Sure wish it was an option last presidential election
2007-04-09 17:22:39 · answer #8 · answered by bkjordam 2 · 1⤊ 1⤋
That's the only way I'll vote this time 'round.
2007-04-09 15:13:19 · answer #9 · answered by . 7 · 1⤊ 0⤋
Well, you can just choose not to vote for a candidate for that particular office.
2007-04-09 15:17:35 · answer #10 · answered by amg503 7 · 0⤊ 2⤋