2007-04-09 14:57:37 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Remember, infinity is a CONCEPT, not an actual number. There is no log(infinity). However, there is a limit for log(x) as x approaches infinity. Think about it like this: log(x) = y means 10^y = x. As x increases, so does y. Every time that x is multiplied by 10, one is added to y. If x is multiplied by 10 an amount of times that approaches infinity, y will increase by one a number of times that approaches infinity. Thus, the limit for y as x->infinity is equal to infinity, so lim log(x) y->infinity = [infinity].
2007-04-09 15:10:32 · answer #1 · answered by vworldv 2 · 0⤊ 0⤋
think of it like the limit as x approches infinity of the log of x.
either graph the log(x) function in your graphic calculator or imagine it.
It's gonna look like it has an asymptote at x=0 and it's going accross the x axis at x=1, going onto infinity. so there you go
the lim x-> oo log(x) = oo
;-)
2007-04-09 22:07:20 · answer #2 · answered by chemMan 3 · 0⤊ 0⤋
infinite is not a number
so log(infinite )does not make sense
log (x) if x tendes to + infinity tends to +infinity.This makes sense
2007-04-09 22:08:02 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
Do you mean the log of infinity? Let us assume that you do; then log of infinity is infinity
2007-04-09 22:02:04 · answer #4 · answered by kellenraid 6 · 0⤊ 0⤋
i think its inifinite..
log(infinite)= x
10^x=inifinite
so.. 10 ^ infinite = infinte ^^ :P
2007-04-09 22:04:49 · answer #5 · answered by dennis c 1 · 0⤊ 0⤋
also infinite.
As x grows without bound, so will f(x)
Does not exist!
2007-04-09 22:03:23 · answer #6 · answered by MathMark 3 · 0⤊ 0⤋