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The base of a pyramid is a square with sides 230m long. Calculate the length of the diagonal of this square, to the nearest tenth of a metre.

2007-04-09 14:21:32 · 3 answers · asked by shiny 1 in Science & Mathematics ➔ Mathematics

If you have a square of length A, then the diagonal of the square is A√2. So caclulate 230√2 to the nearest tenth.

2007-04-09 14:25:15 · answer #1 · answered by Anonymous · 0⤊ 0⤋

diagonal of base = sqrt(230^2 + 230^2) = sqrt(2*52900) = sqrt(105800) = 325.269 = 325.3 m

2007-04-09 21:25:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋

diagonal = side*sqrt2=339.41m

2007-04-09 21:27:17 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋