INVERSE of FUNTIONS.....?

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INVERSE of FUNTIONS.....?

Please help me. The question says this:

http://img396.imageshack.us/img396/317/poy3nj0.png

I am so confused. How can I solve this?

2007-04-09 13:03:47 · 2 answers · asked by Jayla K 1 in Science & Mathematics ➔ Mathematics

2 answers

Simply reverse the x and y to get x=7-y^2 so y^2=7-x and therefore, y=plus/minus sqrt(7-x).

2007-04-09 13:08:20 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋

y = 7 - x^2

exchange x and y
x = 7 - y^2
x-7 = -y^2
-x + 7 = y^2
y = +/- sqrt(-x + 7)

because it wantst x >/ 0, take the positive inverse function

y = sqrt(-x+7)

the domain is x \< 7

ans: f^-1(x) = sqrt(-x+7), x /< 7

2007-04-09 13:11:36 · answer #2 · answered by 7 · 0⤊ 0⤋