Please include the entire process in which you came into your conclusion to answer this question.
2007-04-09 11:38:39 · 13 answers · asked by Mad Girl 2 in Science & Mathematics ➔ Mathematics
45+46
2007-04-09 11:44:18 · answer #1 · answered by :) 5 · 0⤊ 0⤋
Sum 91
2017-01-17 08:39:48 · answer #2 · answered by ? 4 · 0⤊ 0⤋
45 46
2007-04-09 11:46:30 · answer #3 · answered by bcnd 3 · 0⤊ 0⤋
45 & 46.
Divide 91 by 2 to get 45.5. This is the avergae of the 2 numbers. Add .5 to one and subtract .5 from the other to get whole numbers. Check your answer by adding the numbers.
2007-04-09 11:43:56 · answer #4 · answered by Scott H 3 · 0⤊ 0⤋
91/2=45.5. So the numbers have to be 45 and 46.
2007-04-09 11:41:57 · answer #5 · answered by Anonymous · 0⤊ 0⤋
91 divided by 2 is 45.5 so 45.5 + 45.5 = 91 this can be rewritten as 45 + .5 + 46 - .5 without changing anything. the .5's cancel out so you have 45 + 46 = 91
2007-04-09 11:42:13 · answer #6 · answered by metalluka 3 · 0⤊ 0⤋
Think of the half of 91. The numbers are more or less there
You can do this too: x + (x+1) = 90 and solve for x.
Ana
2007-04-09 11:43:58 · answer #7 · answered by MathTutor 6 · 0⤊ 0⤋
x + (x+1) = 91
2x = 90
x = 45
therefore, one number is 45 and the other is 45 + 1 which is 46
2007-04-09 11:41:48 · answer #8 · answered by Maverick977 2 · 1⤊ 0⤋
the first number is x
the next number is x+1
x + x + 1 = 91
2x = 90
x = 45
the numbers are 45 and 46
2007-04-09 11:42:42 · answer #9 · answered by 7 · 0⤊ 0⤋
n+(n+1)=91
2n+1=91
2n=90
n=45
that is the first number
the second is 45+1 which is 46
so your two numbers are 45 and 46.
2007-04-09 11:45:07 · answer #10 · answered by Rocketman 6 · 0⤊ 0⤋