Four different whole numbers sum to one hundred twenty-five. If you increase one of these numbers by four, decrease another by four, the multuply another by four, and divide the last by four, you will produce four equivalent numbers. What are the four original numbers that sum to 125?
2007-04-09 11:26:12 · 3 answers · asked by Jessica 3 in Science & Mathematics ➔ Mathematics
a + b + c + d = 125
Also,
a + 4 = b - 4 = 4c = d/4
Solve everything in terms of "a" and substitute into the first equation.
b = a+8
c = (a+4)/4
d = 4(a+4) = 4a + 16
Substitute back into the first equation and solve for "a".
a + (a + 8) + (a + 4)/4 + (4a + 16) = 125
25a/4 + 25 = 125
25a/4 = 100
25a = 400
a = 16
Now solve for b, c, and d
b = 24
c = 5
d = 80
2007-04-09 11:36:46 · answer #1 · answered by trojanknight_96 3 · 0⤊ 0⤋
Let your numbers be A,B,C and D
Then A+B+C+D = 125
A+4 = B - 4 = 4*C = D/4
Use the bottom set of equalities to solve for B, C and D in terms of A. Then substitute them in the first equation to get A. Do the same with the other letters and you have your answer
2007-04-09 18:36:09 · answer #2 · answered by Demiurge42 7 · 0⤊ 0⤋
can you show me what the problem looks like?
2007-04-09 18:35:16 · answer #3 · answered by flower 1 · 0⤊ 0⤋