Algebra and Trig question.Please show work. Serious replies only!!?

Question

Simplify: Square root of 81 y^6 divided by 625 x^8

a).9 y^3 / 25 x^4
b). 2 y^3 / 5 x^4
c). 9 y ^2/ 25 x^ 6
d). 18 y^3/ 35 x^ 4

Answer 1

I have to assume that the square root is over the whole expression, and that the 625x^8 are together and in the denominator.

√(81 y^6 / 625 x^8) = (81 y^6 / 625 x^8)^(1/2)

Remember the rule of exponents: (a^b)^c = a^(bc).

(81 y^6 / 625 x^8)^(1/2) =
(9^2 y^6 / 25^2 x^8)^(1/2) =
9y^3 / 25x^4

Answer 2

I like to solve these questions step by step.

sqrt((81y^6)/(625x^8))
= (sqrt(81y^6))/(sqrt(625x^8)) - distribute square root
= (9(sqrt(y^6))/(25(sqrt(x^8)) - solve the first term
= (9(y^3))/(25(x^4)) - simplify the second term

This is an algebra question, not trig.....

Answer 3

permit x be the "different" attitude. Then the 1st attitude could be 2x-15. Complementary angles upload as much as ninety stages. So the equation reads x + (2x-15) = ninety. Simplify, 3x-15 = ninety. upload 15 to the two facets, 3x = one 0 five. Divide the two facets through 3, x = 35. it incredibly is the smaller attitude. the 1st attitude is 2x35-15, it incredibly is fifty 5 stages. it incredibly is the extra effective attitude, so "c" is the respond.

Answer 4

a).9 y^3 / 25 x^4
is the answer.

Answer 5

Do your own homework or you will never learn!

Answer 6

i think its all of the above.
ps if your ever in doubt pick c

Answer 7

a)i dont knwo them at all
b) do you r own hmwk

Answer 8

WTF?
Excuse me, but who the heck do you think you are to expect people to do your homework?

I don't mind helping people, but your "please show work"... seems to indicate that you just want it all handed to you.
Disgusting!

Use your brain.

Answer 9

a)

Answer 10

**DO-IT, YOURSELF!!!!!!!!!!! PEACE