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2007-04-09 09:03:34 · 10 answers · asked by k12 1 in Science & Mathematics Mathematics

10 answers

I assume you want this factored?

Since it is cubic, I am going to be lazy and assume they do not really want to make me sweat too much over the problem. So, I am going to take a guess and say that x + 1 might be a root...

(-x³ + x² - x + 2) / (x + 1) = -x² + 3x + 2

Will you look at that... it divides. (If not, I would have tried x - 1... and if neither worked, I would have been rather irritated.)

So, now we have:
(x + 1)(-x² + 3x + 2)

Solve the quadratic:
x² - 3x - 2 = 0
x² - 3x = 2
x² - 3x + (3/2)² = (3/2)² + 2
(x - 3/2)² = (3/2)² + 2
(x - 1.5)² = 9/4 + 8/4
x - 1.5 = ± sqrt(17/4)
x = 3/2 ± sqrt(17)/2
x = (3 ± sqrt17)/2

Since I negated the quadratic equation in order to solve it, I have to negate one of the factors (does not matter which one), and the factored equation is:

-(x + 1)(x - 1.5 + 0.5sqrt17)(x - 1.5 - 0.5sqrt17)

2007-04-09 09:26:17 · answer #1 · answered by computerguy103 6 · 0 0

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2016-12-15 20:35:10 · answer #2 · answered by ? 4 · 0 0

-x^3+x^2-x+2=0=f(x)=0 ,factorise,-x^2(x-1)-x+2=0

2007-04-09 09:33:15 · answer #3 · answered by Anonymous · 0 0

Well, what about it?
Do you want the graph?
in another form?
solve for x? (I don't think you can)
Please specify your question.

2007-04-09 09:07:56 · answer #4 · answered by anonymousperson 4 · 0 0

hello kina!

what do you mean by this?

are you asking for the graph of this function? or

what/?

2007-04-09 09:20:19 · answer #5 · answered by oscar f 2 · 0 0

solve f(x) = 0?

2007-04-09 09:19:49 · answer #6 · answered by Anonymous · 1 0

well its a cubic with x-intercept of about 1.35321

what do you want?

2007-04-09 09:09:04 · answer #7 · answered by Link 4 · 0 0

What do you want to do with F(x)?

2007-04-09 09:19:49 · answer #8 · answered by steiner1745 7 · 0 0

what do you want me to do with it

2007-04-09 09:14:10 · answer #9 · answered by alex 3 · 0 0

and...? what do you need to do with it

2007-04-09 09:07:56 · answer #10 · answered by de4th 4 · 0 0

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