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2007-04-09 08:59:37 · 13 answers · asked by k12 1 in Science & Mathematics Mathematics

13 answers

You need more information to find a.

2007-04-09 09:02:24 · answer #1 · answered by Scott H 3 · 1 0

the place's the determine. the cubic has 3 roots, 3, 5, a. So those are the three places the place it crosses the x-axis. in any different case, it basically crosses the x-axis as quickly as, and touches it yet all over back. to that end a is 3 or 5. the unmarried root is the place it crosses and the double root, a, is the place it touches.

2016-12-08 22:30:06 · answer #2 · answered by ? 4 · 0 0

Your question has three unknowns Y, X and A. To get an answer, you need at least two more equestions that are totally different than the one provided so that you can find the value of each unknown. If Y squared equals 4*X and 2*Y equals 12. Then A equals 8.9773

2007-04-09 09:13:34 · answer #3 · answered by Anonymous · 0 1

1. Divide both sides by x.
2. Do the math on the whole numbers, subtract, add, etc.
3. Divide the answer of the whole numbers by both sides.
4. The value of a.

1. y/x=[(x-3)(x-5)(x-a)]/x
2.y/x=(-3)(-5)(-a) do the math: y/x=15(-a)
3. (y/x)/15=[15(-a)]/15
4. (y/x)/15= -a

2007-04-16 08:36:34 · answer #4 · answered by ICYCUBE 2 · 0 0

y= (x-3) (x-5) (x-a)
(x-a) = y / ( (x-3) (x-5) )
a = x - y / ( (x-3) (x-5) )

2007-04-09 09:06:57 · answer #5 · answered by Helmut 7 · 2 0

If you set y equal to zero you can find a and it would equal 5 and 3

2007-04-09 09:15:04 · answer #6 · answered by rvn2414 1 · 0 1

well for this particular question the answer will be like this.

y= (x-3)(x-5)(x-a)
now multiply(x-3)(x-5) which is (x^2-8x+15)

there for y= (x^2-8x+15)(x-a)
therefor x-a= y/(x^2-8x+15)

therefor a-x= - (y/(x^2-8x+15)) (multiply both side by - sign)
therefor a = x- (y/(x^2-8x+15))
therefor a =(x(x^2-8x+15)-y)/(x^2-8x+15)

2007-04-09 09:12:45 · answer #7 · answered by Parth 3 · 0 0

when i write x (spuared), that means 2 above that letter, like wise with cubed the number 3 above, and such,

(x-3)(x-5)(x-a) =

{(x-3)(x-5)}(x-a) =

(x(squared) - 5x -3x +15)(x-a) =

{x(squared) - 8x +15) (x-a) =

x(cubed) - xa -8x(squared) - 8xa + 15x -15a =

x(cubed)- 8x(squared) -9xa +15a + 15x =

{x(cubed - 8x(squared) - 15x} - {9xa - 15a} =

{x (squared) -8x - 15} -3(3xa- 15a} =

3a =(3x-15) - {x(squared) - 8x - 15x

3a = -3x + 15 - x(squared) - 8x - 15x

3a = x(squared) - 26x + 15

a = 1/3x(squared) - 26/3 + 15/3

a = 1/3x(squared) -26/3 +5

2007-04-17 08:33:18 · answer #8 · answered by falcons_fu_09 2 · 0 0

A=(Y/(X^2-8X+15)) - X

2007-04-17 06:09:08 · answer #9 · answered by GENE D 1 · 0 0

you need to provide additional information
there is no way to find a with the information you gave.

2007-04-09 09:02:42 · answer #10 · answered by leo 6 · 0 0

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