10 HI + 2 KMnO4 + 3 H2SO4 ---> 5 I2 + 2MnSO4 + K2SO4 + 8 H2O
According to the balanced equation above, how many moles of HI would be necessary to produce 2.5 mol of I2 starting with 4.0 mol of KMnO4 and 3.0 mol of H2SO4?
Can anyone please help us? We've been struggling for hours trying to solve this problem... we've taken an educated that the anwer would be 5.0 moles but we're not really sure... if anyone could please help us and show us step by step how to solve this problem, we would really appreciate it, thank you all in advance!
2007-04-09 08:33:25 · 1 answers · asked by Hola Lola! 2 in Science & Mathematics ➔ Chemistry
2.5molI2 x 10molHI/5molI2 = 5molI2 So that's the answer.
You would also need 2 mols KMnO4 and 1.5mols H2SO4, and you've got way more than that. So those are not limiting reagents.
2007-04-09 08:43:13 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋