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I know that there are a few ways to evaluate trig stuff
Like using the special trianges and looking at the graph
But what about other x's that don't include x=PIE/4, PIE/6, PIE/3 or their multiples?

2007-04-09 08:06:22 · 5 answers · asked by Arielle 1 in Science & Mathematics Mathematics

I want to know how to do without a calculator

2007-04-09 08:12:34 · update #1

5 answers

you will have to use the power series
x-x^3/3! + x^5/5! - x^7/7! ....

2007-04-09 08:16:02 · answer #1 · answered by hustolemyname 6 · 0 0

A is in II quadrant so sin is + and cos and tan are - B is in III quadrant so the two sin and cos are - and tan is + sinA = 3/5 cosA = sqrt[a million-sin^2(A)] = sqrt[a million-9/25] = sqrt[sixteen/25] = -4/5 sinB = -5/13 cosB = sqrt[a million - 25/169] = sqrt[one hundred forty four/169] = -12/13 tanA = sinA/cosA = (3/5) /(-4/5) = -3/4 tanB = sinB/cosB = (-5/13) /(-12/13) = 5/12 sinA = 3/5, cosA = -4/5, tanA = -3/4 sinB = -5/13, cosB = -12/13, tanB = 5/12 a million) sin(A+B) = sinAcosB +cosAsinB=(3/5)(-12/13)+(-4/5)(-5/13) sin(A+B) = -36/sixty 5 + 20/sixty 5 = -sixteen/sixty 5 cos(A+B) = cosAcosB-sinAsinB =(-4/5)(-12/13)- (3/5)(-5/13) cos(A+B) = 40 8/sixty 5 + 15/sixty 5 = sixty 3/sixty 5 tan(A+B)=(tanA+ tanB) /(a million- tanAtanB) tan(A+B) = (-3/4 + 5/12)/(a million - (-3/4)(5/12)) = -(a million/3)/(a million + 5/sixteen) tan(A+B) = -a million/3 /(21/sixteen) = -sixteen/sixty 3

2016-12-08 22:26:39 · answer #2 · answered by ? 4 · 0 0

From a scientific calculator sin(3/5 )=0.5646

2007-04-09 08:15:45 · answer #3 · answered by santmann2002 7 · 0 0

sin .6 = .01 if you are talking degrees

sin .6 = .564 if you are talking radians

2007-04-09 08:11:17 · answer #4 · answered by John S 6 · 0 0

It is PI, not PIE.

For the question, how about using your calculator? :)
I do not think that you can get sin 0.6 using graphs.

2007-04-09 08:15:49 · answer #5 · answered by Murat A 2 · 0 0

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