A beautiful box of candy costs $20. If the box is valued at $19 more than the candy, what is the candy worth? THe answer states that the candy is worth $.50 and the box is worth $19.50, which is $19 more than the candy. Please show me the algebraic equation. I can not grasp why the answer could not be $1.00. $1.00 + $19.00 = $20.00. while $.50 +$19.50=$20.00 too. Thanks,
LM4E
2007-04-09 07:20:00 · 4 answers · asked by lowesman4e 1 in Science & Mathematics ➔ Mathematics
You know that the difference between the box and candy is $19.
So, Box - Candy = 19
You also know that together they cost $20
Box + Candy = 20
If Price of Box = B and Price of Candy=C then we have
B - C = 19
B + C = 20
Add them together:
2B = 39
B = $19.50
Meaning the box costs $19.50 and the candy must cost $0.50.
2007-04-09 07:35:52 · answer #1 · answered by peateargryfin 5 · 0⤊ 0⤋
If the box were 19 and the candy were 1, then the box is not 19 more than the candy.
2007-04-09 07:24:17 · answer #2 · answered by fcas80 7 · 1⤊ 0⤋
Let x = cost of candy
Then x+19 = cost of box
19+2x = toatal cos = 20
2x= 20-19 = 1
x =1/2 dollar = 50 cents.
An old, old version of this is:"If a bottle and a cork cost a dollar and a dime and the bottle costs one dollar more than the cork, how much does the cork cost?". The usual answer is a dime, but the real answer is a nickle.
2007-04-09 07:32:46 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
box = candy + 19
box + candy = 20 = candy + 19 + candy = 2candy = 19
so 2 candy = 1
so candy = 0.50
2007-04-09 07:24:33 · answer #4 · answered by hustolemyname 6 · 1⤊ 0⤋