2007-04-09 06:27:13 · 6 answers · asked by kara w 1 in Science & Mathematics ➔ Mathematics
Take the acceleration (meters per second per second) and multiply by the time of the acceleration (2 seconds) to get the answer: 19.6 meters per second is the speec of the object after 2 seconds.
2007-04-09 06:30:33 · answer #1 · answered by Isaac Laquedem 4 · 0⤊ 0⤋
To find the answer, you must multiply the speed by 2. Therefore, the answer is: 9.8 x 2 = 19.6 m/s
2007-04-09 06:31:44 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a=dv/dt = 9.8 m/s^2
v= 9.8 t +C
When t = 0, v = 0 s0 C =0
when t = 2 , v=9.8(2) =19.6 m/s
2007-04-09 07:02:43 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
George calculated that the ball has the fee 8,a million m/s while it hits the floor. i assume we can use the momentum conservation regulation now. 8,a million m/s * 7.83kg = 5.ninety 8*10^24 * V_earth => V_earth = a million.06*10^-23m/s
2016-12-08 22:18:28 · answer #4 · answered by cavallo 4 · 0⤊ 0⤋
Vf = at + Vi
Vf = (9.8)(2) + 0
Vf = 19.6m/s
2007-04-09 06:30:51 · answer #5 · answered by 7 · 0⤊ 0⤋
19.6 m/s
2007-04-09 06:35:53 · answer #6 · answered by Anonymous · 0⤊ 0⤋