2007-04-09 06:07:03 · 10 answers · asked by navya 1 in Science & Mathematics ➔ Mathematics
Equation:
3*x^2 = 432
Divide both sides by 3
x^2 = 144
Square root both sides
x = +/- 12
2007-04-09 06:10:37 · answer #1 · answered by Lilovacookedrice 3 · 0⤊ 0⤋
You start with an equation that can be derived from the problem:
3(x^2)=432
You want to do the order of operations backwards in this case because you're working backwards to find the original number, x. So you would first divide both sides by 3.
(3(x^2))/3=432/3
This simplifies to x^2=144
Then to get rid of the exponent, you take the square root of both sides:
sqrrt(x^2)=sqrrt(144)
Since the square root of 144 equals 12, you end up with x=12. (this can be positive or negative)
2007-04-09 13:21:22 · answer #2 · answered by dance_inside 3 · 0⤊ 0⤋
The square of the integer is 432/3 or 144, so the integer is 12 (or, if you want to be picky, it could also be -12).
2007-04-09 13:10:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
integer = 12
3x^2 = 432
x^2 = 432/3
x^2=144
x = sqrt of 144
x = 12
2007-04-09 13:14:16 · answer #4 · answered by Jon 5 · 0⤊ 0⤋
3x^2 = 432
divide by 3:
x^2 = 144
x = +- sqrt 144
x = +-12
2007-04-09 13:11:13 · answer #5 · answered by Kathleen K 7 · 0⤊ 0⤋
3x^2=432
3x^2/3=432/3
x^2=144
x=12;-12
2007-04-09 13:10:37 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
3x^2 = 432
x^2 = 144
x = 12
2007-04-09 13:10:03 · answer #7 · answered by SPB 6 · 1⤊ 0⤋
x = ur integer
3x^2 = 432
x^2 = 144
x = +/- 12
2007-04-09 13:10:32 · answer #8 · answered by bob b 3 · 0⤊ 0⤋
x^ = 144
x = 12
2007-04-09 13:12:56 · answer #9 · answered by bobweb 7 · 0⤊ 0⤋
3x^2=432
divide by 3
x^2=144
sqrt both sides
x=12,-12
2007-04-09 13:10:23 · answer #10 · answered by Matthew P 4 · 0⤊ 0⤋