The length of a rectangle is 9 feet more than its width. If the area is 110 feet square, find the lenght and width of the triangel.
2007-04-09 05:55:57 · 5 answers · asked by EboniDimplz 2 in Science & Mathematics ➔ Mathematics
Something happened there. It was supposed to be the area of a rectagle and not a triangle.
2007-04-09 06:05:01 · update #1
Call the length L, width W and area A.
L = W+9
A = LW = 110 sq. ft.
W * (W+9) = 110
W^2 + 9W = 110
W^2 + 9W - 110 = 0
This is a quadratic equation and there is a formula to solve it. (That was not, as far as I know, the case with the previous equation, which is why I didn't stop there.)
All this is, of course, assuming you meant to ask for the length and width of the rectangle. if you really meant to ask about a triangle I'm afraid I can't help you.
2007-04-09 06:02:04 · answer #1 · answered by Amy F 5 · 0⤊ 0⤋
hmmm I am guessing you rectangle or a triangle so I will show you both ways.
Say the width is W and the Length is L
Rectangle:
then the equation is
W * L = Area
W * L = 110
We know the L = W + 9
so W * (W + 9) = 110
W^2 + 9W = 110
Triangle
1/2 W * L = Area
1/2 W * (W+9) = 110
W^2 + 9W = 55
2007-04-09 06:01:35 · answer #2 · answered by jennifer 5 · 0⤊ 0⤋
let w = width
Then l = length = w+9
So A = lw = w(w+9) = 110
w^2+9w-110=0
S solve for w and then get l by adding 9.
2007-04-09 06:02:52 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
for a rectangle, A = lw, so
110 = (w+9)w.
what triangle?
2007-04-09 05:59:22 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
(9+w)w = 110
so 9w + w(sqr) = 110
so 9w+w(sqr)-110=0
2007-04-09 06:02:07 · answer #5 · answered by Gabriel G 3 · 0⤊ 0⤋