2007-04-09 05:49:17 · 5 answers · asked by xpiinkladiiex 2 in Science & Mathematics ➔ Mathematics
cosθ = 0.7833
arccos(cosθ) = θ = arccos(0.7833)
0.6708 (4 d.p.) radians. The calculator will be the one in the first quadrant.
The other will occur at 2π - θ which is 5.6123(4 d.p.)
This is a graph showing the equation cos(x) = 0.7833 between 0 and 2π.
http://img49.imageshack.us/my.php?image=cosjn6.jpg
You notice because of the symmetry, the distance from 0 to x is the same as from the other solution to 2π. The position of it must therefore be 2π - θ.
2007-04-09 06:00:31 · answer #1 · answered by peateargryfin 5 · 0⤊ 0⤋
the least confusing thank you to do it is to attraction to a suitable triangle in quadrant a million (because of the fact that 0
2016-12-08 22:17:30
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answer #2
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answered by cavallo 4
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0⤊
0⤋
cos Θ = 0.7833
Θ = 0.6708 or Θ = 2π - 0.6708 = 2.4708
2007-04-09 05:57:30 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
cosө = .7833
ө = arccos(.7833), 2pi-arccos(.7833)
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Reason:
cosө = cos(2pi-ө)
2007-04-09 05:56:38 · answer #4 · answered by sahsjing 7 · 0⤊ 0⤋
.67rad and 2pi-.67rad
2007-04-09 05:55:42 · answer #5 · answered by Nick L 1 · 0⤊ 0⤋