Approx. what mass of CuSO4 - 5H2o (250 g mol-1) is required to prepare 250 mL of 0.10M copper(II) sulfate solution?
2007-04-09 04:51:41 · 2 answers · asked by boopi 2 in Science & Mathematics ➔ Chemistry
One molar is the same as one mole per litre of solution. to have 0.1 moles per litre = x /0.25, where x is the number of moles of copper sulphate
x= 0.1*0.25= 0.025 moles.
Mass of copper sulphate is the number of moles multiplied by the molar mass of copper sulphate= 0.025*250= 6.25grammes.
2007-04-09 04:59:21 · answer #1 · answered by The exclamation mark 6 · 0⤊ 0⤋
If you multiply the molarity time the volume (in liters) that will give you the number of moles of the solute that you need. Then to get the mass of the solute, multiply the moles by the molar mass, and you've got it...
2007-04-09 11:57:25 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋