one number is 1/5 of another number. The sum of the numbers is 78. Waht is the greater of the two numbers.?

Answer 1

Let x be one number and y be the other then

y = (1/5)x

and

y+x = 78

(1/5)x + x = 78

(6/5)x=78

x = 78*5/6 = 65

The larger number is 65.

Answer 2

the two numbers are precisley 13 and 65. because 13 x 5=
65 which is 1/5.The sum of the numbers is 78 because 65+13
is approximately 78.So the greatest of the two numbers is
65.

Answer 3

Let n be the greater number.
Smaller number is 1/5n.

n + 1/5n = 78
6/5n = 78 Multiply by 5/6
n = 195/3 = 65 is the larger number

Answer 4

Let A = (1/5)*B

Let A + B = 78

B = 78 - A

A = (1/5)*(78 - A)

A = 15.6 - A/5

A + A/5 = 15.6

A(6/5) = 15.6

A = 15.6 / (6/5) = 13

and since A + B = 78

then 13 + B = 78

so B = 78 - 13 = 65

Answer 5

X being the better extensive type and Y being the lesser extensive type x + y = 36 {a million} 2x = 6y {2} Divide the two factors of {2} with 2 to get x = 3y {3} replace x in {a million} with 3y from {3} to get 3y + y = 36 {4} Shortened variety of {4} 4y = 36 So, Y = 9 and X = 3y X = 27 X = 27, Y = 9

Answer 6

lets say 1/5 number is x, then second number is 5x
sum x+5x = 78 implies x = 13 ie first number
second number = 5x = 5x13 = 65 (clearly bigger number)

Answer 7

let one number be "x"
so another number is "(1/5)x"= "x/5"

according to the condition

(x) + (x/5) = 78
(5x+x)/5 = 78
6x/5 = 78
x = 78*5/6
x = 13 * 5
x = 65
other number = 65/5 = 13

ANSWER --- GREATER NUMBER = 65
..................---- SMALLER NUMBER = 13