What is the (H+) in a .1M solution of ascorbic acid?

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What is the (H+) in a .1M solution of ascorbic acid?

C6H8O6, Ka= 8.0x10^-5

2007-04-09 03:28:08 · 2 answers · asked by sdelesio319 1 in Science & Mathematics ➔ Chemistry

2 answers

C6H8O6 <> C6H7O6- + H+
initial concentration
0.1 . . . . . . . . . . . 0 . . . . . . 0

at equilibrium
0.1-x . . . . . . . . . . x . . . . . .x

8.0 10^-5 = (x)(x)/0.1-x

x = 0.00283 M

pH= - log 0.00283=2.55

2007-04-09 03:32:47 · answer #1 · answered by Anonymous · 0⤊ 1⤋

you have the formula

pH = (pKa-logc)/2

pKa = log 1/Ka= log 1/810^-5=4.096

c = 0.1 logc =-1

pH =(4.096-(-1))/2 =2.55

2007-04-09 10:36:09 · answer #2 · answered by maussy 7 · 0⤊ 0⤋