To Factorise the given expression is asking what is a common factor within the bracket that can be 'taken out' of the brackets and still have the same overall outcome?
Let us examine the expression closer
(t² - 5t)
Could have been written as {(t x t ) - (5 xt)}
What 'appears' in each bracket?
Answer - t
So we can rewrite expression as:
t (t - 5)
we have now FACTORISED the original expression ready for the next stage in a longer calculation.
2007-04-10 06:23:55
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answer #1
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answered by Rod Mac 5
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take the highest common factor which is in your case t
t ( t - 5 )
that was the full factorisation of your problem
nothing more
2007-04-09 03:16:14
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answer #2
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answered by emy 3
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Simplifying
t2 + -5t
Reorder the terms:
-5t + t2
Factor out the Greatest Common Factor (GCF), 't'.
t(-5 + t)Final result:t(-5 + t)
2007-04-10 09:44:03
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answer #3
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answered by SHIBZ 2
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t^2-5t
could be simplified down to
t*(t-5) so your roots are 0 and 5
to factorize something you just have to play around with something until you get it down till you can see what the roots are. In this case I just pulled out a t
2007-04-09 03:07:22
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answer #4
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answered by Anonymous
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t square - 5t = 0
take t common..
t*(t-5) = 0
now this expression will be zero if and only if atleast one of them that is, t or (t - 5) is equal to zero...
therefore
either t = o
or
(t - 5) = 0
that is t = 5
2007-04-09 03:21:35
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answer #5
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answered by Suhail 2
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t^2 - 5t
(t x t ) - (5 x t )
't' is common to both sets of brackets, so it can be factored out.
t [(t) - (5)]
t(t - 5) ;{ this means t x (t - 5)}.
2007-04-09 09:50:37
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answer #6
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answered by lenpol7 7
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i luv maths. T^2 -5T
Rememver this same as
(TxT)-(5xT)
you can see that t is comon in the 2 brackets so just take it out
T(T-5).
this is the answer
2007-04-09 03:23:34
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answer #7
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answered by GOC 1
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t^2 - 5t = t (t-5)
2007-04-09 03:20:38
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answer #8
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answered by the DoEr 3
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t^2 - 5t
Factor the greatest common monomial; in this case, it's just t.
t(t - 5)
2007-04-09 03:06:28
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answer #9
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answered by Puggy 7
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t squared - 5t
t(t-5)
2007-04-09 03:10:35
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answer #10
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answered by Aruna R 2
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