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Factorise: t squared - 5t

how do you do it?

2007-04-09 03:03:40 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

To Factorise the given expression is asking what is a common factor within the bracket that can be 'taken out' of the brackets and still have the same overall outcome?

Let us examine the expression closer

(t² - 5t)

Could have been written as {(t x t ) - (5 xt)}
What 'appears' in each bracket?

Answer - t
So we can rewrite expression as:

t (t - 5)

we have now FACTORISED the original expression ready for the next stage in a longer calculation.

2007-04-10 06:23:55 · answer #1 · answered by Rod Mac 5 · 0 0

take the highest common factor which is in your case t
t ( t - 5 )
that was the full factorisation of your problem
nothing more

2007-04-09 03:16:14 · answer #2 · answered by emy 3 · 1 0

Simplifying
t2 + -5t

Reorder the terms:
-5t + t2

Factor out the Greatest Common Factor (GCF), 't'.
t(-5 + t)Final result:t(-5 + t)

2007-04-10 09:44:03 · answer #3 · answered by SHIBZ 2 · 0 0

t^2-5t

could be simplified down to

t*(t-5) so your roots are 0 and 5

to factorize something you just have to play around with something until you get it down till you can see what the roots are. In this case I just pulled out a t

2007-04-09 03:07:22 · answer #4 · answered by Anonymous · 0 0

t square - 5t = 0

take t common..

t*(t-5) = 0

now this expression will be zero if and only if atleast one of them that is, t or (t - 5) is equal to zero...

therefore
either t = o

or

(t - 5) = 0
that is t = 5

2007-04-09 03:21:35 · answer #5 · answered by Suhail 2 · 0 0

t^2 - 5t
(t x t ) - (5 x t )
't' is common to both sets of brackets, so it can be factored out.
t [(t) - (5)]
t(t - 5) ;{ this means t x (t - 5)}.

2007-04-09 09:50:37 · answer #6 · answered by lenpol7 7 · 0 0

i luv maths. T^2 -5T
Rememver this same as
(TxT)-(5xT)
you can see that t is comon in the 2 brackets so just take it out
T(T-5).
this is the answer

2007-04-09 03:23:34 · answer #7 · answered by GOC 1 · 0 0

t^2 - 5t = t (t-5)

2007-04-09 03:20:38 · answer #8 · answered by the DoEr 3 · 0 0

t^2 - 5t

Factor the greatest common monomial; in this case, it's just t.

t(t - 5)

2007-04-09 03:06:28 · answer #9 · answered by Puggy 7 · 0 1

t squared - 5t
t(t-5)

2007-04-09 03:10:35 · answer #10 · answered by Aruna R 2 · 0 1

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