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fr = 1 / 2pie * squareroot of inductor*capacitor

how would you solve for capacitor?

2007-04-09 02:50:17 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

10k =frenquency resonance and inductor = .010 henry

2007-04-09 03:02:31 · update #1

2 answers

C = ( 1 / 2*pi*f )^2 / L =

= (1/(2*pi*10000))^2 /.01 = 2.53 * 10^-8 Farads


C = 2.53 * 10^-8 Farads

2007-04-09 03:06:01 · answer #1 · answered by Anonymous · 0 0

You need to fill in the inductance and frequency values first.
Otherwise, just algebraicly rearrange the equation.

2007-04-09 09:54:39 · answer #2 · answered by dogsafire 7 · 0 0

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