If you can repeat the digits (ie. have numbers like 4477 and 4444) then its 9 to the power of 4 (9*9*9*9) or 6561.
If not, it's 9*8*7*6, or 3024.
2007-04-09 01:07:48
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answer #1
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answered by Hosebeast-ess to be 4
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3024 4-digit numbers can be made. Here is how you solve it:
we need 4 digits so here they are _ _ _ _
for the first digit you have 9 numbers you could place, which leaves 8 numbers for the 2nd digit, 7 numbers for the 3rd digit and 6 numbers for the 4th digit.
so you multiply 9.8.7.6 = 3024
A way to prove this method is this:
lets say that the question asked us how many 3 digit numbers can be made wşth the digits 1-3. My method tells us that 3.2=6 numbers can be made. Lets check it
123, 132, 231, 213, 312, 321
As you see you can't make more than 6 numbers. I hope this answered your question.
If you can repeat the numbers your anwer would be 9.9.9.9
2007-04-09 01:12:45
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answer #2
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answered by guru 3
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There is 21 combinations of 4 digit numbers you can make using 1 - 9 assuming you are using each digit only once.
2007-04-09 01:10:05
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answer #3
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answered by fuck off 5
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If you are allowing repeats of the 9 numbers, you can have 9^4 possibilities.
If no repeats of the numbers from 1-9 are allowed, you can have (9 * 8 * 7 * 6) = 3024 possibilities
2007-04-09 01:05:45
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answer #4
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answered by Bhajun Singh 4
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the posibility of a first, second, third and fourth might be from 1 to 9...so
9 X 9 X 9 X 9 = 6561 ways
2007-04-09 01:17:52
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answer #5
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answered by Anonymous
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9*9*9*9=6561
2007-04-09 01:10:09
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answer #6
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answered by iyiogrenci 6
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3024.
you multiply 9x8x7x6
2007-04-09 01:06:27
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answer #7
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answered by Anna-L 1
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