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2 answers

Yes. A capacitive circuit will have the steady-state current leading the voltage.

Inductive equipment causes the current to lag the voltage.

99% of the load on an electrical distribution system is either resistive or inductive. The overall result is a lagging power factor.

Capacitors are added to the circuit to bring the power factor closer to unity.

I learned it as ELI the ICE man.

Voltage (E) is ahead of Current (I) in an Inductive (L) circuit. ELI
Current (I) leads the voltage (E) in a Capacitive (C) circuit. ICE

2007-04-08 13:15:06 · answer #1 · answered by Thomas C 6 · 0 0

Yup. ELI likes ICE is the menomic.

2007-04-08 13:09:03 · answer #2 · answered by Doug B 3 · 0 0

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