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A DNA polymorphism close to the gene CYP1A1 has two alleles, 1 and 2. Possession of at least one copy of allele 2 makes a person particularly sensitive to the carcinogenic effects of cigarette smoke. The frequency of allele 2 is 0.1. From this figure we predict that, for this reason, 19% of people in the population will be at an elevated risk of developing cancer from smoking.

Can u give an explanation please.

Thank you

2007-04-03 07:32:56 · 2 answers · asked by Anonymous in Science & Mathematics Medicine

2 answers

Each of us has two alleles of the CYP1A1 gene (one allele form each parent). Therefore, we each have a 10% chance (0.1) of having at least one allele from each parent with the polymorphism. Since we therefore have TWO chances of having one allele, we have 0.1 plus 0.1 chances of at least one allele. This would equal a total of 0.2 (20%) chance of at least one allele.

Since we have a 1% chance of having both alleles with the polymorphism (0.1 X 0.1 = 0.01 = 1%), we need to subtract this 'redundancy of risk' from our 20% chance. This yields a final risk of 20% - 1% = 19%.

Hope this helps. Best wishes and good luck.

2007-04-03 08:35:28 · answer #1 · answered by Doctor J 7 · 0 0

This is true and I'll email you my answer why!!!

VERY NICE!!!! ;)

2007-04-03 07:54:35 · answer #2 · answered by Anonymous · 0 0

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