Many thanks to those who responded earlier but those answers were not quite addressing what I was looking for.
I am thinking of the case of a typical pole mounted single phase distribution xmfr with loads on both sides of the center tap. If the secondary of the transformer is center tapped and the other two leads from the secondary are going from positive to negative with the AC current, that means that the center tap is either more negative or more positive than either outside lead at any given time.
If at a given instant the top lead is positive, then the center tap is more negative than the top lead. The current should flow from the top lead to the center tap. However, isn't the center tap more positive than the bottom lead at that same instant? Wouldn't the current therefor flow out of it into the bottom lead? (assuming loads connected to both sides of the tap) Flowing inward from the top lead and outward to the bottom lead at the same time. How does that work?
2007-04-02
11:46:25
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5 answers
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asked by
Sand M
1
in
Science & Mathematics
➔ Engineering