is there any formulas i can use to determine the amount of friction between to surfaces given known variables. i want to know how to calculate losses due to friction. so i need to know how to calculate friction.
2007-03-31 16:46:54 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
Here this may help.
2007-03-31 16:57:38 · answer #1 · answered by Spike [850] 1 · 0⤊ 0⤋
Generally the surface will have some sort of coefficient of friction which you can then apply to the equation D = Fc where D is the Frictional force, F is the 'normal' or in other words orthogonal force to the surface, and c is the coefficient of friction. The most common cause of problems on a question like this is using gravitational force instead of the normal force.
2007-03-31 16:51:20 · answer #2 · answered by v_2tbrow 4 · 0⤊ 0⤋
The state of the art for engineers to calculate friction is simply empirical. the equations quoted above for "newtons friction" are simply a mathematical exercise that take experimental measurements and put them into an "equation". to understand if any of this applies to your problem, you have to go back and find out under what circumstances the experiments were done to see how "similar" they might be to your situation. The problem with empirical data like this is they are NOT derived from our fundemental understanding of physics. because of this, they do not take into account all factors affecting the forces. the "coefficient of friction" really has lumped into it a lot of factors, some of which we have no understanding of at all, and neither is it "constant" .
one drop of oil, one drop of water, one grain of sand, changes in temperature, surface wear, humidity, all throw calculations based on bulk properties of the materials in a cock hat. so beware, just plugging in numbers may result in a non-sense solution to a real world problem.
2007-04-01 07:54:30 · answer #3 · answered by lare 7 · 0⤊ 0⤋
The formulation is y=x^2-2x. you could plug interior the values of x to cajole your self that that's right. right that's how I resolve those issues. First, I see if there are any aspects i will multiply x via to get y in each and each equation. If no longer, I attempt aspects which i ought to multiply x via and then subtract some to get y. I fool around with the arithmetic to make certain if i'm getting close. If no longer, ;I attempt 2 issues. First, I make a graph of x vs. y and notice what the curve feels like. for this reason it regarded like a parabola. At that factor , via fact that i comprehend a parabola has a term of x^2 in it, I squared the x's to make certain how x^2 bearing directly to y. i spotted that 4^2=sixteen replaced into 8 extra suitable than y and eight^2=sixty 4 replaced into sixteen extra suitable than y=40 8. Then I appeared for a development. Aha! 8=2x and sixteen=2x for the 2nd equation, so attempt it for the subsequent one--4=2x, 25-15=10=2x So I see that for the duration of each and each case x^2 is extra suitable than y via 2x. In different words, to locate y, sq. x and subtract 2x. subsequently, y=x^2-2x
2016-11-25 03:17:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Hmm....this isn't a question where one can answer with a sentence or two at yahoo answers. You need a textbook and learn about the static and kinetic forces. Only if I had my highschool physics textbook...
2007-03-31 16:54:16 · answer #5 · answered by John L 2 · 0⤊ 0⤋
yes
(frictional force)=(coefficient of friction)x(normal force)
2007-03-31 16:52:37 · answer #6 · answered by Archangel 4 · 0⤊ 0⤋
"is there" ? oh my goodness.
2007-03-31 16:50:06 · answer #7 · answered by cindy p 3 · 0⤊ 1⤋